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How many total atoms are in 1 mole of(NH_(4))_(2)Cr_(2)O_(7) ? |
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Answer» `6.22xx10^(23)` `= 2 [ N + 4 H] + 2Cr + 7 (O)` `= 2 (1+4) + 2 + 7` `= 19` atoms per `(NH_(4))_(2) Cr_(2)O_(7)`. 1 mole `(NH_(4))_(2) Cr_(2)O_(7)= 6.022xx10^(23)` atoms `= 114.418xx10^(23)` atoms `~~114.47xx10^(23)` atoms |
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