1.

How many total atoms are in 1 mole of(NH_(4))_(2)Cr_(2)O_(7) ?

Answer»

`6.22xx10^(23)`
`114.47xx10^(23)`
`84xx10^(23)`
19

Solution :NUMBER of atoms in 1 MOLECULES of `(NH_(4))_(2) Cr_(2)O_(7)`
`= 2 [ N + 4 H] + 2Cr + 7 (O)`
`= 2 (1+4) + 2 + 7`
`= 19` atoms per `(NH_(4))_(2) Cr_(2)O_(7)`.
1 mole `(NH_(4))_(2) Cr_(2)O_(7)= 6.022xx10^(23)` atoms
`= 114.418xx10^(23)` atoms
`~~114.47xx10^(23)` atoms


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