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How many unit cells are present in a cube -Shaped ideal crystal of NaCl of mass 1.00 g ?[ Atomic mass : Na = 23, Cl = 35.5 ] |
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Answer» ` 5.14 XX 10^(21)` `(4 xx 58.5)/(6.-02 xx 10^(23)) g` No. of unit cells is 1 g = `(6.02 xx 10^(23))/(4xx 58.5)` ` = 2 .57 xx 10^(21)` |
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