1.

How many unit cells are present in a cube -Shaped ideal crystal of NaCl of mass 1.00 g ?[ Atomic mass : Na = 23, Cl = 35.5 ]

Answer»

` 5.14 XX 10^(21)`
` 1.28 xx 10^(21)`
`1.71xx 10^(21)`
`2.57 xx 10^(21)`

SOLUTION :One unit CELL has 4 NaCl UNITS, i.e, has mass
`(4 xx 58.5)/(6.-02 xx 10^(23)) g`
No. of unit cells is 1 g = `(6.02 xx 10^(23))/(4xx 58.5)`
` = 2 .57 xx 10^(21)`


Discussion

No Comment Found