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How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g ? [Atomic mass : Na=23 , Cl=35.5] |
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Answer» `5.14xx10^21` `therefore` No. of unit cell in 1 g =`(6.02xx10^23)/(4xx58.5)` `=2.57xx10^21` |
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