1.

How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g ? [Atomic mass : Na=23 , Cl=35.5]

Answer»

`5.14xx10^21`
`1.28xx10^21`
`1.71xx10^21`
`2.57xx10^21`

SOLUTION :ONE UNIT CELL HAS4 NaCl units , i.e., has mass `=(4xx58.5)/(6.02xx10^23)`g
`therefore` No. of unit cell in 1 g =`(6.02xx10^23)/(4xx58.5)`
`=2.57xx10^21`


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