How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g ? [Atomic mass:Na=23,Cl=35.5]

How many unit cells are present in a cube-shaped ideal crystal of NaCl

1.	How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g ? [Atomic mass:Na=23,Cl=35.5]
Answer» `2.57times10^(21)`unit CELLS `5.14times10^(21)`unit cells `1.28times10^(21)`unit cells Solution :No. of `NA^(+)Cl^(-)`units in ONE unit cell =4 Mass of 1 unit cell `=(4(23+35.5))/(6.02times10^(23))g=((58.5times4)/(6.02times10^(23)))g` No. of unit cells in 1 g `=(6.02times10^(23))/(58.5times4)=602/(58.5times4)=10^(21)=2.57times10^(21)`