How many unpaired electorns are present in the ground state of fe^(3+)(z=26),Mn^(2+)(Z=25) and argon(Z=18)?

How many unpaired electorns are present in the ground state of fe^(3+)

1.	How many unpaired electorns are present in the ground state of fe^(3+)(z=26),Mn^(2+)(Z=25) and argon(Z=18)?
Answer» Solution :`F to Fe^(3+)+3e^(-)` Fe(Z=26)`Fe^(3+)`=number of electrons=23 `1s^(2)2s^(2)2p^(6)3P^(6)3D^(6)4s^(2)`for Fe atom. `1s^(2)2s^(2)2p^(6)3s^(6)3d^(5) for Fe^(3+)ion.` So,it CONTAIN 5 unpaired electrons. `Mn toMn^(2+)+2e^(-)` Number of unpaired electrons in `Mn^(2+)=5` AR(Z=18)Electronic configuration is `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)` All ORBITALS are completely filled.So,no unpaired electrons in it.