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How many words can be formed using all the letters of the folloiwng words ? (i) BANANA (ii) ALLAHABAD INDEPENDENCE (iv) ASSASSINATION |
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Answer» (i) We have word BANANA Letters are B, (N N), (A A A). `therefore` Number of words `=(6!)/(2!xx3!)=(6xx5xx4)/(2!)=60` (ii) We have word ALLAHABAD Letters are (A A A A), (L L), H,B,D `therefore` Number of words `=(9!)/(4!xx2!)=(9xx8xx7xx6)/(2!)=1512` (iii) We have word INDEPENDENCE Letters are I, (N N N), (D D), (E E E E),P,C. `therefore` Number of words `=(12!)/(3!xx2!xx4!)` (iv) We have word ASSANSSINATION Letters are (A A A), (S S S), (II), (N N), T, O. `therefore` Number of words `=(13!)/(3!xx4!xx2!xx2!)` |
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