1.

How manyelementscan beaccommodated in the presentset upof theformof the periodictable ?Explain.

Answer»

Solution :In thepresent SET up tothe longformof theperiodic tablewe havesevenperiods (i.e., principalquantum number n=7) and four blocks (s,p,d- andf- block elements ) . Thereforethe maximumnumberof elements whichcan beaccommodated in thepresentset up of the longformof theperiodictable in theaccordancewithaufbauprinciple is
`1 s^(2)2 s^(2)2P^(6)3 s^(2)3p^(6)3 d^(10)4p^(6)5s^(2)4d^(10)5 p^(6)6s^(2) 4 f^(14) 5 d^(10)6 p^(6) 7 s^(2)5 f^(14)6 d^(10)7 p^(6) = 118`


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