How may gram of 83.4% pure sodium sulphate can be produced form 250 g

1.	How may gram of 83.4% pure sodium sulphate can be produced form 250 g of 95% pure NaCl.
Answer» `288.2g` `237.5g` `345.4g` `187.2g` Solution :`2NaCl+H_(4)SO_(4)rarrNa_(2)SO_(4)+2HCl` Amount of PURE `NaCl=250xx(95)/(100)=237.5g` `2xx58.5gNaCl-142gNa_(2)SO_(4)` `237.5gNaCl-288.2gNa_(2)SO_(4)` To get 83.4 pure `Na_(2)SO_(4)` - take 100G impure sample of `Na_(2)SO_(4)` To get 288.2g pure `Na_(2)SO_(4)` - take 345.4g impure `Na_(2)SO_(4)`

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