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How may millilitres of a `9 N H_(2)SO_(4)` solution will be required to neutralize completely `20mL` of a `3.6 N NaOH` solution ?A. `18.0mL`B. `8. 0 Ml`C. `16.0mL`D. `80.0 mL` |
Answer» Correct Answer - 2 `N_(NaOH)=3.6" "," "V_(NaOH)=20" "," "N_(H_(2)SO_(4))=9" "," "V_(H_(2)SO_(4))=?` `V_(H_(2)SO_(4))=(3.6xx20)/(9)=8mL` |
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