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How may moles of oxygen are present in 400 cm^(3) sample of the gas at a pressure of 760 mm of Hg at a temperature of 310K. (The value of R 1 s 8.31 kP a dm^(-3) K^(-1) "mol"^(-1)) |
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Answer» Solution :Here value of R is given in SI unit : pressure and VOLUME is expressed in Kpa and `DM^(3)` . Thus `P=760 mm 101*3 kPa, v=400 cm^(3) =400xx10^(-3) dm^(3)` According to ideal GAS equation. `pv=nRT` `n=(pv)/(RT)=(101*3xx0*40)/(8*31xx310)=0*01572` `:. n=1 1*57xx10^(-2) "mol"` |
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