1.

How methane reacts with Cl_(2) in the presence of light ?

Answer»

Solution :`underset("Methane")(CH_(4) + ) Cl_(2) OVERSET("light") underset(HCl)(to) underset("CHLORIDE") underset("methyl")(CH_(3)Cl) overset(Cl_(2)) underset(-HCl)(to) underset("chloride") underset("Methylidene")(CH_(2)Cl_(2))overset(Cl_(2))underset(HCl)(to) underset("CHLOROFORM") (CHCl_(3)) overset(Cl_(4)) underset(-HCl)(to) underset("Carbon tetra- chloride")(C Cl_(4))`


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