How much Ca(NO_(3))_(2) in mg must be present in 50 ml of a solution with 2.35 ppm of Ca?

How much Ca(NO_(3))_(2) in mg must be present in 50 ml of a solution w

1.	How much Ca(NO_(3))_(2) in mg must be present in 50 ml of a solution with 2.35 ppm of Ca?
Answer» `0.1175` `770.8` `4.7` `0.48` Solution :Water density 1g/ML `10^(6)g` (`10^(6)` ml) water CONTAINS 2.35g CA 50ml (50G) water contains `(50xx2.35)/(10^(6))GCA` `=(50xx2.35)/(10^(6))xx10^(3)mgCa=0.1175gCa` `40gCa-164gCa(NO_(3))_(2)` `0.1175Ca-0.48g Ca(NO_(3))_(2)`