InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
How much charge is required for the following reaction? (i) 1mol of `Al^(3+)` to Al. (ii) 1 mol of `Cu^(2+)` to Cu. (iii) 10 mole of `MnO_(4)^(-)` to `Mn^(2+)` |
|
Answer» (i) The electrode reaction is: `Al^(3+)+3e^(-)toAl` `therefore` Quantity of charge required for reduction of 1 mole of `Al^(3+)=3F=3xx96500C=289500C`. (ii) The electrode reaction is: `Cu^(2+)+2e^(-)toCu` `therefore`Quantity of charge required for reduction of 1 mol of `Cu^(2+)=2` faradays`=2xx96500C=193000C` ltBrgt (iii) The electrode reaction is `MnO_(4)^(-)toMn^(2+)`, i.e., `Mn^(7+)5e^(-)toMn^(2+)` `therefore`Quantity of charge required `=5F=5xx96500C=482500C`. |
|