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How much Charge is required for the following reductions `:` `a. 1 mol of Al^(3+) to Al` `b.` ` 1 mol of Cu^(2+) to Cu` `c.` `1 mol of MnO_(4)^(-)` to `Mn^(2+)?` |
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Answer» (i) `" " Al^(3+)(aq)+underset(3" Faraday")(3e^(-))toAl(s)` `"Charge" =3xxF=3xx96500" C"= 2.895xx10^(5)C` (ii) `" " Cu^(2+)(aq)+ underset(2 " Faraday")(2e^(-))toCu(s)` `"Charge"=2xxF=2xx96500" C "=1.93xx10^(5) C`. (iii) `" " underset(O.N. of Mn=+7)(MnO_(4)^(-))+5e^(-) to underset(O.N. of Mn=+2)(Mn^(2+))` `"Charge"=5xxF=5xx96500" C"=4.825xx10^(5)" C"`. |
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