1.

How much charge is required for the following reductions? (i) 1 mol of Al3+ to Al (ii) 1 mol of Cu2+ to Cu (iii) 1 mol of MnO4- to Mn2+

Answer»

(i) Al3+ + 3e → Al 

charge required = 3F 

(ii) Cu2+ + 2e → Cu 

charge required = 2F 

(iii) MnO4- + 8H+ + Se→ Mn2+ + H2

charge required = 5F



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