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How much copper can be obtained from 100 g of copper sulphate (CuSO_(4))? |
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Answer» Solution :MOLAR mass of `CuSO_(4) = 63.5 + 32 + (4 xx 16) = 159.5 G mol^(-1)` 1 mole (159.5 g) of `CuSO_4` contains 1 g atom (63.5 g) of copper. Amount of copper that can be obtained from 100 g of copper sulphate. `=(63.5)/159.5 xx 100 = 39.81 g` |
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