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how much distance will car moving with a uniform acceleration of 4 MS as to cover in 5 second if internal velocity of the car is 5m​

Answer» <html><body><p>Acceleration , a = 4m/s²Time <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> , t = 5sInitial velocity , u = 5m/sTo Find:-Distance covered by car ,<a href="https://interviewquestions.tuteehub.com/tag/ssolution-2279386" style="font-weight:bold;" target="_blank" title="Click to know more about SSOLUTION">SSOLUTION</a>:-Firstly we calculate the Final velocity.By using <a href="https://interviewquestions.tuteehub.com/tag/1st-283090" style="font-weight:bold;" target="_blank" title="Click to know more about 1ST">1ST</a> <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of motion• v = u+atSubstitute the <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> we get→ v = 5+4×5→ v = 25m/sNow , using 3rd equation of motion• v² =u² + 2asSubstitute the value we get→ 25² = 5² + 2×4 ×s→ 625 = 25 × 8×s→ 625 - 25 = 8×s→ 600 = 8×S→ S = 600/8→ S = 75 mTherefore, the distance covered by the car is 75m.</p></body></html>


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