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how much distance will car moving with a uniform acceleration of 4 MS as to cover in 5 second if internal velocity of the car is 5m |
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Answer» Acceleration , a = 4m/s²Time TAKEN , t = 5sInitial velocity , u = 5m/sTo Find:-Distance covered by car ,SSOLUTION:-Firstly we calculate the Final velocity.By using 1ST EQUATION of motion• v = u+atSubstitute the VALUE we get→ v = 5+4×5→ v = 25m/sNow , using 3rd equation of motion• v² =u² + 2asSubstitute the value we get→ 25² = 5² + 2×4 ×s→ 625 = 25 × 8×s→ 625 - 25 = 8×s→ 600 = 8×S→ S = 600/8→ S = 75 mTherefore, the distance covered by the car is 75m. |
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