1.

How much energy is required to ionise a hydrogen atom if the electron occupies n=5 orbit ? Compare your answer with the ionisation energy of hydrogen atom (energy required to remove the electron from n=1 orbit).

Answer»

Solution :`E_(n)=-(21.8xx10^(-19))/n^(2)" J ATOM"^(-1)`
For ionization from 5TH ORBIT, `n_(1)=5, n_(2)=OO`
`:. Delta E=E_(2)-E_(1)=-21.8xx10^(-19) (1/n_(2)^(2)-1/n_(1)^(2))=21.8xx10^(-19) (1/n_(1)^(2)-1/n_(2)^(2))=21.8xx10^(-19) (1/5^(2) -1/oo)`
`=8.72xx10^(-20) J`
For ionization from 1st orbit, `n_(1)=1, n_(2)=oo`
`Delta E'=21.8xx10^(-19) (1/1^(2)-1/oo)=21.8xx10^(-19) J`
`(Delta E')/(Delta E)=(21.8xx10^(-19))/(8.72xx10^(-20))=25`
Thus, the energy required to remove electron from 1st orbit is 25 times than that required to remove electron from 5th orbit.


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