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How much energy is required to ionise an `H` atom if the electron occupies `n=5` orbit? Compare your answer with the ionisation enthaply of `H` atom (anargy required to remove the electronic from `n=1` orbit). |
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Answer» `E_(n)=((2.18xx10^(-18)J))/(n^(2))` `=(2.18xx10^(-18)J)/(5^(2))=8.72xx10^(-20)J` `1E` of `H=(2.18xx10^(-18)J)/((1)^(2))=2.18xx10^(-18)J` |
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