1.

How much energy is required to ionise an `H` atom if the electron occupies `n=5` orbit? Compare your answer with the ionisation enthaply of `H` atom (anargy required to remove the electronic from `n=1` orbit).

Answer» `E_(n)=((2.18xx10^(-18)J))/(n^(2))`
`=(2.18xx10^(-18)J)/(5^(2))=8.72xx10^(-20)J`
`1E` of `H=(2.18xx10^(-18)J)/((1)^(2))=2.18xx10^(-18)J`


Discussion

No Comment Found

Related InterviewSolutions