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How much energy is required to separate the typical middle mass nucleus `._(50)^(120)Sn` into its constituent nucleons ? (Mass of `._(50)^(120)Sn=119.902199u`, mass of proton = 1.007825u and mass of neutron = 1.008665u) |
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Answer» `m_(P)=1.007825u` `m_(n)=1.008665u` For Sn, Z = 50, A = 120, M = 119.902199u (i) Mass defect `Delta m` `= [Zm_(P)+(A-Z)m_(n)-M]u` `= 50(1.007825)+(120-50)[(1.008665) - 119.902199]` `= [50xx1.007825+70xx1.008665 - 119.902199]u` `= [50.39125+70.60655-119.902199]u` `Delta M = [120.9978-119.902199]` `= 1.095601 u` (ii) Energy required to separate the nucleons = B.E of the nucleus `BE=Delta Mc^(2)=Delta M xx931.5 MeV` `= 1.095601xx931.5 MeV` `= 1020.5 MeV` |
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