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How much heat energy is released when 5g of water at 20°C changes to ice at 0°C? [Specific heat capacity of water = 4.2Jg-1 °C-1 Specific latent heat of fusion of ice = 336Jg-1] |
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Answer» θ = mcΔθ + mL = 5 x 4.2 x 20 + 5 x 336 = 420 + 1,680 = 2,100Joule |
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