1.

How much heat is evolved when 12 g of CO reacts with NO2? The reaction is : 4CO(g) + 2NO2(g)  → 4CO2(g)  + N2(g), ΔrH0 = -1200 kJ

Answer»

Given :

4CO(g) + 2NO2(g)  → 4CO2(g)  + N2(g)

Molar mass of CO = 28 g mol-1

ΔrH0 = -1200 kJ;

Molar mass of CO = 28 g mol-1

mco = 12 g, 

ΔH = ?

From the reaction,

∵ For 4 × 28 g CO, 

ΔH0 = – 1200 kJ

∵ For 12g CO 

ΔH0\(\frac{(-1200)\times 12}{4\times 28}\)

= -128.6 kJ

∴ Heat evolved = 128.6 kJ



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