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How much heat is evolved when 12 g of CO reacts with NO2? The reaction is : 4CO(g) + 2NO2(g) → 4CO2(g) + N2(g), ΔrH0 = -1200 kJ |
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Answer» Given : 4CO(g) + 2NO2(g) → 4CO2(g) + N2(g) Molar mass of CO = 28 g mol-1 ΔrH0 = -1200 kJ; Molar mass of CO = 28 g mol-1 mco = 12 g, ΔH = ? From the reaction, ∵ For 4 × 28 g CO, ΔH0 = – 1200 kJ ∵ For 12g CO ΔH0 = \(\frac{(-1200)\times 12}{4\times 28}\) = -128.6 kJ ∴ Heat evolved = 128.6 kJ |
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