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How much heat is required to raise the temperature of 10kg of water by 30 degrees C? |
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Answer» We know that, to change the STATE of a matter, heat is required. Heat required to change a solid into liquid is GIVEN by , Q=mL , where L= latent heat of fusion , now given that , m=10 kg , and latent heat of fusion of ICE is , L=336×10 3 J/kg , hence, heat required to CONVERT the 10kg of ice at 0 o C to water at 0 C , Q=(10×336×10 3 )=3360 kJ , now, heat required to convert the 10kg of water at 0 o C to water at 50 o C , by , Q ′ =m×c×Δt , given c=4200J/kg o C , hence Q ′ =10×4200×(50−0)=2100 kJ , therefore total heat required to convert 10kg of ice at 0 o C to water at 50 o C , Q ′′ =Q+Q ′ =3360+2100=5460 kJ |
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