1.

How much heat is required to raise the temperature of 10kg of water by 30 degrees C?

Answer»

We know that, to change the STATE of a matter, heat is required. Heat required to change a solid into liquid is GIVEN by ,

Q=mL ,

where L= latent heat of fusion ,

now given that , m=10 kg , and latent heat of fusion of ICE is , L=336×10

3

J/kg ,

hence, heat required to CONVERT the 10kg of ice at 0

o

C to water at 0

C ,

Q=(10×336×10

3

)=3360 kJ ,

now, heat required to convert the 10kg of water at 0

o

C to water at 50

o

C ,

by , Q

=m×c×Δt ,

given c=4200J/kg

o

C ,

hence Q

=10×4200×(50−0)=2100 kJ ,

therefore total heat required to convert 10kg of ice at 0

o

C to water at 50

o

C ,

Q

′′

=Q+Q

=3360+2100=5460 kJ



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