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How much hight above the ground a mancan throw a ball if he is able to throw the same ball upto maximum distance of `60 m? |
Answer» Her, `R _(max)=60 m`. As, `R_(max) =u^(2) /g , so 60 =u^(2)/g` …(i) Let (h) be the maximum height attained by the ball. Taking vertical upward motion of ball upto maximum height (h), we have `u&(y) =u, a)(y) =- g, u_(y) =0, y=0` As v_(y)^(2) =u_(y)^(2) +2 a)(y) y` :. 0=u^(2) +2 (-g) h` or `h=u^(2)/(2 g) =1/2 xx 60 =30 m`. |
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