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How much is x – 2y + 3z greater than 3x + 5y – 7? |
Answer» By subtracting x – 2y + 3z from 3x + 5y – 7 we can get the required expression, Required expression = (x – 2y + 3z) – (3x + 5y – 7) = x – 2y + 3z – 3x – 5y + 7 Collecting positive and negative like terms together, we get = x – 3x – 2y + 5y + 3z + 7 = –2x – 7y + 3z + 7 |
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