1.

How much mass is there approximately in 1 L of mercury (Hg)? 

Answer»

A volume of 1 L equals 0.001 m3, 

 the density is in the range of 10000 kg/m3 

so we get

m = ρV = 10 000 kg/m3 × 0.001 m3 = 10 kg

A more accurate value  is ρ

= 13580 kg/m3

For the air  1 kg/m3 so we get

m = ρV = 1 kg/m3 × 0.001 m3 = 0.001 kg

 A more accurate value is ρ

= 1.17 kg/m3 at 100 kPa, 25°C. 



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