How much mass of sodium acetate is required to make 250 mL of 0.575 molaraqueous solution?

How much mass of sodium acetate is required to make 250 mL of 0.575 mo

1.	How much mass of sodium acetate is required to make 250 mL of 0.575 molaraqueous solution?
Answer» 11.79 g 15.38 g 10.81 g 25.35 g Solution :MOLAR MASS of sodium ACETATE `(CH_3COONa)` =82.0245 g/mol Mass of `CH_3COONa` required to make 250 mL of 0.575M solution `=(0.575xx82.0245xx250)/(1000)=11.79g`