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How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m/s2. |
Answer» Mass of the dumbbell, m = 10 kg Distance covered by the dumbbell, s = 80 cm = 0.8 m Acceleration in the downward direction, a = 10 m/s2 Initial velocity of the dumbbell, u = 0 Final velocity of the dumbbell (when it was about to hit the floor) = v According to the third equation of motion: v2 = u2 + 2as v2 = 0 + 2 (10) 0.8 v = 4 m/s Hence, the momentum with which the dumbbell hits the floor is = mv = 10 × 4 = 40 kg m s−1 |
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