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How much of NaOH is reuired to neutralise 1500 `cm^(3)` of 0.1 N HCl (Na=23)?A. 40 gB. 4 gC. 6 gD. 60 g |
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Answer» Correct Answer - C `N=(W(gm)xx1000)/(Vxx"Eq. wt.")` 1500 ml of `0.1 N HCl =150 ml` (N) `1=(W(gmxx1000))/(150xx40), W(gm)=(150xx40)/1000=6 gm`. |
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