1.

How much of NaOH is reuired to neutralise 1500 `cm^(3)` of 0.1 N HCl (Na=23)?A. 40 gB. 4 gC. 6 gD. 60 g

Answer» Correct Answer - C
`N=(W(gm)xx1000)/(Vxx"Eq. wt.")`
1500 ml of `0.1 N HCl =150 ml` (N)
`1=(W(gmxx1000))/(150xx40), W(gm)=(150xx40)/1000=6 gm`.


Discussion

No Comment Found

Related InterviewSolutions