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How much of NaOH is reuired to neutralise 1500 `cm^(3)` of 0.1 N HCl (Na=23)?A. (a)40 gB. (b)4 gC. (c )6 gD. (d)60 g |
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Answer» Correct Answer - C `N=(W(g)xx1000)/(VxxEq. Wt.)` `1500 ml of 0.1 N HCl=150 ml(N)` `1=(W(g)xx1000)/(150xx40), W(g)=(150xx40)/1000=6 g` |
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