1.

How much PCl_(5) must be added to a one litre vessel at 250^(@)C in order to obtain a 35 concentration of 0.1 mol of Cl_(2)? K_(c) for PCl_(5) hArr PCl_(3)+Cl_(2) is 0.0414 mol L^(-1)

Answer»


Solution :`{:(,PCl_(5),hArr,PCl_(3),+,Cl_(2)),("INITIAL moles",a,,0,,0),("moles at",(a-0.1),,0.1,,0.1),("EQUILIBRIUM",,,,,):}`
`:. K_(c)=(0.1/1xx0.1/1)/((a-0.1)/1) ( :' "volume is" 1 L)`
`0.0414=0.01/((a-0.1))` or `a=0.3415 "mol"`


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