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How much PCl_(5) must be added to a one litre vessel at 250^(@)C in order to obtain a concentration of 0.1 mole of chlorine ? Equilibrium constant for the dissociation of PCl_(5) " at " 250^(@)C " is " 0.0414. |
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Answer» `K_(C) = ([PCl_(3)][CL_(2)])/([PCl_(5)]) , 1.e., 0*0414 = (0*1 xx 0*1)/(a-0*1)` This gives a = `0*3415` mole |
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