1.

How much PCl_(5) must be added to a one litre vessel at 250^(@)C in order to obtain a concentration of 0.1 mole of chlorine ? Equilibrium constant for the dissociation of PCl_(5) " at " 250^(@)C " is " 0.0414.

Answer»


Solution :`{:(,PCl_(5),HARR,PCl_(3),+,Cl_(2)),("Intial","a mole",,,,),(" At EQM.",(a-0*1),,0*1,,0*1 "mol " L^(-1)):}`
`K_(C) = ([PCl_(3)][CL_(2)])/([PCl_(5)]) , 1.e., 0*0414 = (0*1 xx 0*1)/(a-0*1)`
This gives a = `0*3415` mole


Discussion

No Comment Found