How much steam at 100^(@)C is to be passed into water of mass 100 g at 20^(@)C to raise its temperature by 5^(@)C? (Latent heat of steam is 540 cal/g and specific heat of water is 1cal//g""^(@)C)

How much steam at 100^(@)C is to be passed into water of mass 100 g at

1.	How much steam at 100^(@)C is to be passed into water of mass 100 g at 20^(@)C to raise its temperature by 5^(@)C? (Latent heat of steam is 540 cal/g and specific heat of water is 1cal//g""^(@)C)
Answer» Solution :Heat lost by steam = heat gained by water `m_(s)L_(s)+m_(s)S(100-t)=m_(W)s(t-20)`, where `m_(s)` is the mass of steam, `L_(s)` is the LATENT heat of steam, s is the SPECIFIC heat of water and `w_(s)` is the mass of water. Here, `L_(s)=540cal//g,s=1cal//g""^(@)C,m_(w)=100g`, `t=20+5=25^(@)C` `m_(s)xx540+m_(s)XX1(100-25)=100xx1(25-20)` `m_(s)xx615=500" "thereforem_(s)=500/615=0.813g`.