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How much time heater will take to increase the temperature of 100g water by `50^(@)C` if resistance of heating coat is `484Omega` and supply voltage is 220V a.c.

Answer» Heat given by heater=heat taken by water
`rArr (V^(2))/(R)t=ms J Delta theta rArr t=(ms J Delta thetaR)/(V^(2))rArr t=((100xx10^(-3))(4.2xx10^(3))(50)xx484)/(220xx22 0)=210s`


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