1.

How much volume of 11.2 volumes H_2O_2 is required to completely oxidise one mole of lead sulphide into lead sulphite?

Answer»

2Its
4Its
6 Its
0.5 Its

Solution :`PbS+ 4H_2O_2 to PbSO_4+4H_2O`
1 mole Z4 mole
`22.4 vol H_2O_2 = 2M H_2O_2`
11.2 vol `H_2O_2 = 1M H_2O_2 = 1 " mole" //"lt"`


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