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How much volume of carbon dioxide is produced when 50 g of calcium carbonate is heated completely under standard condition ? |
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Answer» Solution :The balanced chemical equation is. `CaCO_(3) (s) rarr`CaO(s) + `CO_(2)` (g) As per the STOICHIOMETRIC equation. 1 MOLE (100G) `CaCO_(3)` on heating produces I mole `CO_(2)` ![]() At STP. 1 mole of `CO_(2)` OCCUPIES a volume of 22.7 litres `:.` At STP, 50 g of `CaCO_(3)` on heating produces, `("22.7 litersof" CO_(2))/(cancel(100g CaCO_(3))_2) xx 50g CaCO_(3)` = 11.35 liters of `CO_(2)` |
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