1.

How much volume of carbon dioxide is produced when 50 g of calcium carbonate is heated completely under standard condition ?

Answer»

Solution :The balanced chemical equation is.
`CaCO_(3) (s) rarr`CaO(s) + `CO_(2)` (g)
As per the STOICHIOMETRIC equation.
1 MOLE (100G) `CaCO_(3)` on heating produces I mole `CO_(2)`

At STP. 1 mole of `CO_(2)` OCCUPIES a volume of 22.7 litres
`:.` At STP, 50 g of `CaCO_(3)` on heating produces,
`("22.7 litersof" CO_(2))/(cancel(100g CaCO_(3))_2) xx 50g CaCO_(3)`
= 11.35 liters of `CO_(2)`


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