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How much water should be added to `2M HCl` solution to form `1"litre"` of `0.5M HCl` ? . |
Answer» Let `V` be initial volume Then mol of `HCl` = constant `2 xx V = 1 xx 0.5 " "rArr" " V =0.25 L` Volume of water added `=1 - 0.25 = 0.75 L` . |
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