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How much will the reduction potential of a hydrogen electrode change when its solution initially at `pH=0` is neutralized to `pH=7` ?A. Increase by `0.059 V`B. Decrease by `0.058 V`C. Increase by `0.41 V`D. Decrease by `0.41 V` |
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Answer» Correct Answer - D `E ^(@) = E + (0.059)/(1)log 10^(-7)` `= E^(@) + (0.059 xx (-7))/(1) = E^(@) -0.41 V` |
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