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InterviewSolution
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How much work must work be done by a force on 50 kg body in order to accelerate it in the direction of force from rest to `20 ms^(-1)` is 10 s?A. `10^(-3) J`B. `10^(4) J`C. `2xx10^(3) J`D. `4 xx10^(4) J` |
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Answer» Correct Answer - B As, equation of motion is `v=u+at implies 20 =0+a xx 10` `20=a xx10 implies a=2 m//s^(2)` Now, distance `s=ut+1/2 at^(2)` `implies s=0+1/2 xx2xx10xx10` or `s=100 m` `W=F.s ="mas"=50xx2xx100=10^(4) J` |
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