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Answer» APPENDING an ampersand (&) to the end of datatype MAKES a variable ELIGIBLE to use as reference variable. int a = 20; int& b = a; The first statement initializes a an integer variable a. Second statement creates an integer reference initialized to variable a TAKE a look at the below example to see how reference variables work. int main () { int a; int& b = a; a = 10; cout << "Value of a : " << a << endl; cout << "Value of a reference (b) : " << b << endl; b = 20; cout << "Value of a : " << a << endl; cout << "Value of a reference (b) : " << b << endl; return 0; } Above code creates following output. Value of a : 10 Value of a reference (b) : 10 Value of a : 20 Value of a reference (b) : 20 Appending an ampersand (&) to the end of datatype makes a variable eligible to use as reference variable. int a = 20; int& b = a; The first statement initializes a an integer variable a. Second statement creates an integer reference initialized to variable a Take a look at the below example to see how reference variables work. int main () { int a; int& b = a; a = 10; cout << "Value of a : " << a << endl; cout << "Value of a reference (b) : " << b << endl; b = 20; cout << "Value of a : " << a << endl; cout << "Value of a reference (b) : " << b << endl; return 0; } Above code creates following output. Value of a : 10 Value of a reference (b) : 10 Value of a : 20 Value of a reference (b) : 20
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