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How To Define A Function With Any Number Of Arguments?

Answer»

If you want to define a FUNCTION with any number of arguments, you need to:
•Declare the function with no argument.
•Call func_num_args() in the function to get the number of the arguments.
•Call func_get_args() in the function to get all the arguments in an array.
Here is a PHP SCRIPT on how to handle any number of arguments:
<?php
function myAverage() {
$COUNT = func_num_args();
$args = func_get_args();
$sum = array_sum($args);
return $sum/$count;
}
$AVERAGE = myAverage(102, 121, 105);
print("Average 1: $average\n");
$average = myAverage(102, 121, 105, 99, 101, 110, 116, 101, 114);
print("Average 2: $average\n");
?>
This script will print:
Average 1: 109.33333333333
Average 2: 107.66666666667

If you want to define a function with any number of arguments, you need to:
•Declare the function with no argument.
•Call func_num_args() in the function to get the number of the arguments.
•Call func_get_args() in the function to get all the arguments in an array.
Here is a PHP script on how to handle any number of arguments:
<?php
function myAverage() {
$count = func_num_args();
$args = func_get_args();
$sum = array_sum($args);
return $sum/$count;
}
$average = myAverage(102, 121, 105);
print("Average 1: $average\n");
$average = myAverage(102, 121, 105, 99, 101, 110, 116, 101, 114);
print("Average 2: $average\n");
?>
This script will print:
Average 1: 109.33333333333
Average 2: 107.66666666667



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