How to differentiate y = 3y3 + 4x2 + 2x + 2xy + 1with respect to x?

1.	How to differentiate y = 3y3 + 4x2 + 2x + 2xy + 1with respect to x?
Answer» The derivative ofy = 3y³ + 4x² + 2x + 2xy + 1 with respect to x is dy / dx = (8x + 2y + 2) / (1 - 2x - 9y²). Differentiation is one of the most important concepts in calculus. The slopes of differentcurves at different points can be found using differentiation.

Discussion