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How to prepare 4 mili equivalent per litre Ca solution from CaCo3 |
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Answer» Answer: Molar mass (CaCO3) = M(Ca) + M(C) + 3 x M(O) = 40 + 12 + 3 x 16 = 100 g/mole. Divide the molar mass by the ion CHARGE or oxidation number (for CaCO3) to determine equivalent (EQ.) weights. Explanation: good MORNING all of you |
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