How to solve 1 - 3x - 3y - 4(x + y)2

1.	How to solve 1 - 3x - 3y - 4(x + y)2
Answer» 1 - 3x -3y -4(x+y)² = 4 -3 -3x -3y -4(x+y)² = 4(1-(x+y)² ) -3(1+x+y) = 4(1²-(x+y)² ) -3(1+x+y) = 4{(1-x-y)(1+x+y)}-3(1+x+y) = (1+x+y) {4(1-x-y)-3} (1+x+y) {4-4x-4y-3) ⇒ (1+x+y) (1-4x-4y)

Answer»

1 - 3x -3y -4(x+y)²

= 4 -3 -3x -3y -4(x+y)²

= 4(1-(x+y)² ) -3(1+x+y)

= 4(1²-(x+y)² ) -3(1+x+y)

= 4{(1-x-y)(1+x+y)}-3(1+x+y)

= (1+x+y) {4(1-x-y)-3} (1+x+y) {4-4x-4y-3)

⇒ (1+x+y) (1-4x-4y)

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How to solve 1 - 3x - 3y - 4(x + y)2

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