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How to write the slope-intercept form of the equation of the line described; (-2, -1) parallel to y = -3/2x - 1?

Answer» How to write the slope-intercept form of the equation of the line described; (-2, -1) parallel to y = -3/2x - 1?

Given y= (-3/2)x - 1 and point (-2, -1)



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