How we can calculate "n factor" for redox reaction? for example, calculate n factor for this reaction: I2 + 2Na2S2O3 ==> Na2S4O6 + 2NaI

How we can calculate "n factor" for redox reaction? for example, cal

1.	How we can calculate "n factor" for redox reaction? for example, calculate n factor for this reaction: I2 + 2Na2S2O3 ==> Na2S4O6 + 2NaI
Answer» Sodium THIOSULPHATE is very good reductant. When it react with iodine then the reaction is as follow. I2 + 2Na2S2O3 = Na2S4O6 + 2NaIAt first oxidation number of sulphate atom is +2. After the reaction the oxidation number become +2.5.In the reaction TWO sulphate atoms are present. So oxidation number change = 2*0.5 = 1We know n factor is the oxidation number change in a molecule. So here n factor is +1.