How will you calculate the partial pressure in terms of mole fraction

1.	How will you calculate the partial pressure in terms of mole fraction ?
Answer» Solution :MIXUTRE containing three GASES, 1,2 and 3 with partial pressure `p_(1), P_(2) and p_(3)`in container with volume v, the TOTAL pressure `P_("total")` will be given by `P_("total") p_(1)+p_(2)+p-(3)""....(1)` Assuming that the gases behave ideally, `p_(1)=n_(1)(RT)/(V), p_(2)=n_(2) (RT)/(V), p_(3) =n_(3) (RT)/(V)` `P_("total")=n_(1)(RT)/(V)+n_(2)(RT)/(V)+n_(3)(RT)/(V)` `=(n_(1)+n_(2)+n_(3))(RT)/(V)` `P_("total")=n_("total") ((RT)/(V)) ""....(2)` The partial pressure can also be EXPRESSED as`((RT)/(V))` can expressed as `(p_(1))/(n_(1)) or (p_(2))/(n_(2)) or (p_(3))/(n_(3)) or` in general `(p-(i))/(n_(i))` Therefore `P_("total")=n_("total")(p_(i))/(n_(i))=(n_("Total"))/(n_(1))p-(i)` `rArr p_(i) =(n_(i))/n_("total") p_("total")=x_(i)P_("Total") ""....(3)` Where `x^(i)` is themole FRACTION of the `i^(th)` component.

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