1.

How will you connect, in series and parallel, 24 cells each of internal resistance 2 ohm so as to get max current across the load 10ohm?

Answer»

Let n=number of cells in each row,
m=number of rows joined in parallel,
Therefore, mn=24  ..............(1)
Power output across load is maximum when R=nr/m
or 10=[n/m x 2]
or n=5m  ...........(2)
From (1) and (2), we get
m x 5m = 24
5m2=24

m2 = 24/5

Now find the value of m and n you will get the answer.



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