1.

How will you convert benzene in to (a) p-nitrobromobenzene (b) m-nitrobromobenzene

Answer»

Solution :(a) Benzene into p-nitrobromobenzene : <BR> `C_(6)H_(6)+Br_(2)` (In presence of an hyd. `FeBr_(3)`) `rarr C_(6)H_(5)Br+HBr`
`C_(6)H_(5)Br + Conc. HNO_(3) + Conc. H_(2)SO_(4) rarr` p-nitrobromobenzene
(b) Benzene into m-nitrobromobenzene:
`C_(6)H_(6) + Conc. HNO_(3) + Conc. H_(2)SO_(4) rarr C_(6)H_(5)NO_(2)`
`C_(6)H_(5)NO_(2)+ Br_(2)` (In presence of ANHY. `FeBr_(3)`) r `rarr` m-nitrobromobenzene.


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