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How will you convert benzene in to (a) p-nitrobromobenzene (b) m-nitrobromobenzene |
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Answer» Solution :(a) Benzene into p-nitrobromobenzene : <BR> `C_(6)H_(6)+Br_(2)` (In presence of an hyd. `FeBr_(3)`) `rarr C_(6)H_(5)Br+HBr` `C_(6)H_(5)Br + Conc. HNO_(3) + Conc. H_(2)SO_(4) rarr` p-nitrobromobenzene (b) Benzene into m-nitrobromobenzene: `C_(6)H_(6) + Conc. HNO_(3) + Conc. H_(2)SO_(4) rarr C_(6)H_(5)NO_(2)` `C_(6)H_(5)NO_(2)+ Br_(2)` (In presence of ANHY. `FeBr_(3)`) r `rarr` m-nitrobromobenzene. |
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