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How will you convert benzene into (i)p-nitrobromobenzene , (ii) m-nitrobromobenzene |
Answer» SOLUTION :(II)Here, since the substituents are at m-position w.r.t. to each other , therefore, the first SUBSTITUENT in the benzene ring should be m-directing (i.e., `NO_2`) and then the other group (i.e., Br) should be introduced .Therefore, the sequence of REACTIONS is
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